32x^2+64x-184=0

Solution for 32x^2+64x-184=0 equation:

32x^2+64x-184=0

a = 32; b = 64; c = -184;
Δ = b2-4ac
Δ = 642-4·32·(-184)
Δ = 27648
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{27648}=\sqrt{9216*3}=\sqrt{9216}*\sqrt{3}=96\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-96\sqrt{3}}{2*32}=\frac{-64-96\sqrt{3}}{64}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+96\sqrt{3}}{2*32}=\frac{-64+96\sqrt{3}}{64}
$